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Two cursortool for standard dev of fastline

http://216.92.101.67/support/viewtopic.php?f=4&t=11300

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Two cursortool for standard dev of fastline

Posted: Wed Jul 07, 2010 2:09 pm
by 13056035
Hi,

I would like to make two cursor(vertical) and know in real time the value of each cursor.
So, I write this:

Code: Select all


        Steema.TeeChart.WPF.Tools.CursorTool Cursor_left;
        Steema.TeeChart.WPF.Tools.CursorTool Cursor_right;

        Cursor_left = new Steema.TeeChart.WPF.Tools.CursorTool(tChart1.Chart);
        Cursor_left.Style = Steema.TeeChart.WPF.Tools.CursorToolStyles.Vertical;         

        Cursor_right = new Steema.TeeChart.WPF.Tools.CursorTool(tChart1.Chart);
        Cursor_right.Style = Steema.TeeChart.WPF.Tools.CursorToolStyles.Vertical;
            
        //label1.Content = Cursor1.GetHorizAxis.ToString();
        double xVal = Cursor_left.XValue;
        int index = tChart1[0].XValues.IndexOf(xVal);
         
        double yVal = tChart1[0].YValues[index];
        tChart1.Header.Text = xVal.ToString() + " - " + yVal.ToString();
        tChart1.Header.Visible = true;
But I can't arrive to have these values of each cursor.
And after, I want the standard deviation of all point between the two cursors.

I use visual studio 2008 with WPF and STEEMA 3.5.3188.18562

Thanks

Re: Two cursortool for standard dev of fastline

Posted: Wed Jul 07, 2010 4:43 pm
by 13056035
Hey,

I tried a new code with cursor but I had an exception as you can see on picture below :

Image

Uploaded with ImageShack.us

The code C# is attached of this message.

Good evening for everybody !!

Re: Two cursortool for standard dev of fastline

Posted: Fri Jul 09, 2010 8:09 am
by yeray
Hi ljoli,

You could try doing something similar to the example in the Features demo, at All Features\Welcome !\Chart styles\Standard\Line(Strip)\Interpolating line series

Re: Two cursortool for standard dev of fastline

Posted: Fri Jul 09, 2010 8:44 am
by 13056035
Thanks for your answer.

I have not see this example. I will try.


Good day

Re: Two cursortool for standard dev of fastline

Posted: Fri Jul 09, 2010 8:53 am
by 13056035
When I try the interpolating example one error arrive :

Error 1 'Steema.TeeChart.WPF.Tools.CursorTool' does not contain a definition for 'change' and no extension method 'change' accepting a first argument of type 'Steema.TeeChart.WPF.Tools.CursorTool' could be found (are you missing a using directive or an assembly reference?) C:\Users\xxx\Documents\Visual Studio 2008\Projects\training_pt\WpfApplication9\WpfApplication9\Window1.xaml.cs 150 30 WpfApplication9


Why?

Re: Two cursortool for standard dev of fastline

Posted: Fri Jul 09, 2010 8:58 am
by 13056035
I show you my code :

Code: Select all

            // use cursors
            this.Cursor_left = new Steema.TeeChart.WPF.Tools.CursorTool();
            this.tChart1.Tools.Add(this.Cursor_left);
            this.Cursor_left.Style = Steema.TeeChart.WPF.Tools.CursorToolStyles.Vertical;            
            //color of cursor
            Cursor_left.Pen.Color = System.Windows.Media.Colors.Green;
            this.Cursor_left.Pen.Color = Colors.Green;
            this.Cursor_left.change += new Steema.TeeChart.WPF.Tools.CursorChangeEventHandler(this.cursorTool1_Change);

Re: Two cursortool for standard dev of fastline

Posted: Fri Jul 09, 2010 9:46 am
by yeray
Hi ljoli,

Here it is the Interpolate example translated to WPF:

Code: Select all

        public Window1()
        {
            InitializeComponent();
            InitializeChart();
        }

        private Steema.TeeChart.WPF.Styles.Line line1;
        private Steema.TeeChart.WPF.Styles.Line line2;
        private Steema.TeeChart.WPF.Styles.Line line3;
        private Steema.TeeChart.WPF.Tools.CursorTool cursorTool1;
        private double xval;

        private void InitializeChart()
        {
            tChart1.Aspect.View3D = false;

            line1 = new Steema.TeeChart.WPF.Styles.Line(tChart1.Chart);
            line2 = new Steema.TeeChart.WPF.Styles.Line(tChart1.Chart);
            line3 = new Steema.TeeChart.WPF.Styles.Line(tChart1.Chart);

            line1.Pointer.Style = Steema.TeeChart.WPF.Styles.PointerStyles.Rectangle;
            line2.Pointer.Style = Steema.TeeChart.WPF.Styles.PointerStyles.Circle;
            line3.Pointer.Style = Steema.TeeChart.WPF.Styles.PointerStyles.Triangle;

            cursorTool1 = new Steema.TeeChart.WPF.Tools.CursorTool(tChart1.Chart);
            cursorTool1.FollowMouse = true;
            cursorTool1.Style = Steema.TeeChart.WPF.Tools.CursorToolStyles.Vertical;
            cursorTool1.Change += new Steema.TeeChart.WPF.Tools.CursorChangeEventHandler(cursorTool1_Change);

            tChart1.AfterDraw += new Steema.TeeChart.WPF.PaintChartEventHandler(tChart1_AfterDraw);

            foreach (Steema.TeeChart.WPF.Styles.Line s in tChart1.Series)
            {
                s.Pointer.Visible = true;
                s.Pointer.HorizSize = 3;
                s.Pointer.VertSize = 3;
                s.FillSampleValues(20);
            }
        }

        void cursorTool1_Change(object sender, Steema.TeeChart.WPF.Tools.CursorChangeEventArgs e)
        {
            xval = e.XValue;
            tChart1.Header.Text = "";
            for (int i = 0; i < tChart1.Series.Count; i++)
                if (tChart1.Series[i] is Steema.TeeChart.WPF.Styles.Custom)
                {
                    tChart1.Header.Text += tChart1.Series[i].Title + ": Y(" + e.XValue.ToString("0.00") + ")= ";
                    tChart1.Header.Text += InterpolateLineSeries(tChart1.Series[i] as Steema.TeeChart.WPF.Styles.Custom, e.XValue).ToString("0.00") + "\r\n";
                }
        }

        void tChart1_AfterDraw(object sender, Steema.TeeChart.WPF.Drawing.Graphics3D g)
        {
            int xs = (int)tChart1.Axes.Bottom.CalcXPosValue(xval);
            int ys;
            g.Brush.Visible = true;
            g.Brush.Solid = true;
            for (int i = 0; i < tChart1.Series.Count; i++)
                if (tChart1.Series[i] is Steema.TeeChart.WPF.Styles.Custom)
                {
                    ys = (int)tChart1.Series[i].GetVertAxis.CalcYPosValue(InterpolateLineSeries(tChart1.Series[i] as Steema.TeeChart.WPF.Styles.Custom, xval));
                    g.Brush.Color = tChart1.Series[i].Color;
                    g.Ellipse(new Rect(xs - 4, ys - 4, 8, 8));
                }

        }

        private double InterpolateLineSeries(Steema.TeeChart.WPF.Styles.Custom series, int firstindex, int lastindex, double xvalue)
        {
            int index;
            for (index = firstindex; index <= lastindex; index++)
            {
                if (index == -1 || series.XValues.Value[index] > xvalue) break;
            }
            // safeguard
            if (index < 1) index = 1;
            else if (index >= series.Count) index = series.Count - 1;
            // y=(y2-y1)/(x2-x1)*(x-x1)+y1
            double dx = series.XValues[index] - series.XValues[index - 1];
            double dy = series.YValues[index] - series.YValues[index - 1];
            if (dx != 0.0) return dy * (xvalue - series.XValues[index - 1]) / dx + series.YValues[index - 1];
            else return 0.0;
        }

        private double InterpolateLineSeries(Steema.TeeChart.WPF.Styles.Custom series, double xvalue)
        {
            return InterpolateLineSeries(series, series.FirstVisibleIndex, series.LastVisibleIndex, xvalue);
        }

Re: Two cursortool for standard dev of fastline

Posted: Fri Jul 09, 2010 10:01 am
by 13056035
Ok Cool That is works very well 8)

Thanks and good day Yeray

Re: Two cursortool for standard dev of fastline

Posted: Fri Jul 09, 2010 3:16 pm
by 13056035
The example of interpolating works but I can't do my objective.

I want the Y value of each cursor for know the standard deviation between the two cursors.
The problem : I can not take the value of each cursor because the function CHANGE return a VOID :!:

like that :

Code: Select all

        void cursor_right_Change(object sender, Steema.TeeChart.WPF.Tools.CursorChangeEventArgs e)
        {
            label1.Content = "";
            for (int j = 0; j < tChart1.Series.Count; j++)
                if (tChart1.Series[j] is Steema.TeeChart.WPF.Styles.Custom)
                {
                label1.Content = InterpolateLineSeries(tChart1.Series[j] as Steema.TeeChart.WPF.Styles.Custom, e.XValue).ToString("0.00") + "\r\n";
                    //string val_cursor_right
                }
        }

Re: Two cursortool for standard dev of fastline

Posted: Tue Jul 13, 2010 9:16 am
by yeray
Hi ljoli,

But you can use global variables, isn't it?
I've simplified the example above. Now you can see only a line series and two cursor tools. And I've added a calc method where you could calculate what you want, for example, the interpolation positions, as I do.

Code: Select all

        public Window1()
        {
            InitializeComponent();
            InitializeChart();
        }

        private Steema.TeeChart.WPF.Styles.Line line1;
        private Steema.TeeChart.WPF.Tools.CursorTool Cursor_left;
        private Steema.TeeChart.WPF.Tools.CursorTool Cursor_right;
        private double val_cursor_left, val_cursor_right;
        int x_left, x_right, y_left, y_right;

        private void InitializeChart()
        {
            tChart1.Aspect.View3D = false;

            line1 = new Steema.TeeChart.WPF.Styles.Line(tChart1.Chart);
            line1.Pointer.Style = Steema.TeeChart.WPF.Styles.PointerStyles.Rectangle;
            line1.Pointer.Visible = true;
            line1.Pointer.HorizSize = 3;
            line1.Pointer.VertSize = 3;
            line1.FillSampleValues(20);

            Cursor_left = new Steema.TeeChart.WPF.Tools.CursorTool(tChart1.Chart);            
            Cursor_left.Style = Steema.TeeChart.WPF.Tools.CursorToolStyles.Vertical;
            Cursor_left.Change += new Steema.TeeChart.WPF.Tools.CursorChangeEventHandler(Cursor_left_Change);

            Cursor_right = new Steema.TeeChart.WPF.Tools.CursorTool(tChart1.Chart);
            Cursor_right.Style = Steema.TeeChart.WPF.Tools.CursorToolStyles.Vertical;
            Cursor_right.Change += new Steema.TeeChart.WPF.Tools.CursorChangeEventHandler(Cursor_right_Change);

            tChart1.AfterDraw += new Steema.TeeChart.WPF.PaintChartEventHandler(tChart1_AfterDraw);
        }

        void Cursor_left_Change(object sender, Steema.TeeChart.WPF.Tools.CursorChangeEventArgs e)
        {
            val_cursor_left = e.XValue;
            recalc();
        }

        void Cursor_right_Change(object sender, Steema.TeeChart.WPF.Tools.CursorChangeEventArgs e)
        {
            val_cursor_right = e.XValue;
            recalc();
        }

        private void recalc()
        {
            x_left = (int)tChart1.Axes.Bottom.CalcXPosValue(val_cursor_left);
            x_right = (int)tChart1.Axes.Bottom.CalcXPosValue(val_cursor_right);
            y_left = (int)tChart1[0].GetVertAxis.CalcYPosValue(InterpolateLineSeries(tChart1[0] as Steema.TeeChart.WPF.Styles.Custom, val_cursor_left));
            y_right = (int)tChart1[0].GetVertAxis.CalcYPosValue(InterpolateLineSeries(tChart1[0] as Steema.TeeChart.WPF.Styles.Custom, val_cursor_right));
        }

        void tChart1_AfterDraw(object sender, Steema.TeeChart.WPF.Drawing.Graphics3D g)
        {
            g.Brush.Visible = true;
            g.Brush.Solid = true;
            g.Brush.Color = tChart1[0].Color;
            g.Ellipse(new Rect(x_left - 4, y_left - 4, 8, 8));
            g.Ellipse(new Rect(x_right - 4, y_right - 4, 8, 8));
        }

        private double InterpolateLineSeries(Steema.TeeChart.WPF.Styles.Custom series, int firstindex, int lastindex, double xvalue)
        {
            int index;
            for (index = firstindex; index <= lastindex; index++)
            {
                if (index == -1 || series.XValues.Value[index] > xvalue) break;
            }
            // safeguard
            if (index < 1) index = 1;
            else if (index >= series.Count) index = series.Count - 1;
            // y=(y2-y1)/(x2-x1)*(x-x1)+y1
            double dx = series.XValues[index] - series.XValues[index - 1];
            double dy = series.YValues[index] - series.YValues[index - 1];
            if (dx != 0.0) return dy * (xvalue - series.XValues[index - 1]) / dx + series.YValues[index - 1];
            else return 0.0;
        }

        private double InterpolateLineSeries(Steema.TeeChart.WPF.Styles.Custom series, double xvalue)
        {
            return InterpolateLineSeries(series, series.FirstVisibleIndex, series.LastVisibleIndex, xvalue);
        }

Re: Two cursortool for standard dev of fastline

Posted: Tue Jul 13, 2010 1:11 pm
by 13056035
Hi Yeray,

Thanks for your example, I was looking for a way to build this function with a global variable.

Another thing:

How to define the initial value of one cursor ??
is it like that ?

Code: Select all


// initial position
double init_value;
init_value = 200;
Cursor_left.XValue = init_value;
Thank you again for all

LJ

Re: Two cursortool for standard dev of fastline

Posted: Tue Jul 13, 2010 1:44 pm
by 13056035
ok for the initial value I see on this topic -> http://www.teechart.net/support/viewtop ... f=4&t=9888 :!:

for init the value of cursor I do this :

Code: Select all


// initial position
Cursor_left.XValue = 100;
Cursor_left.YValue = 100;
Cursor_left.XValue = 100;
Thanks :mrgreen:

Re: Two cursortool for standard dev of fastline

Posted: Tue Jul 13, 2010 2:37 pm
by yeray
Hi ljoli,

It was also discussed here and there you'll find another workaround proposed.

Re: Two cursortool for standard dev of fastline

Posted: Thu Jul 15, 2010 10:48 am
by 13056035
Another problem with the "cursor.change"

Now I use a CSV file for build my fastline. And I use all code before but I had an exception

Image

Uploaded with ImageShack.us

I attached my code on this post.


Best regards

LJ

Re: Two cursortool for standard dev of fastline

Posted: Thu Jul 15, 2010 11:05 am
by 13056035
The exception has arrive when I want to move one cursor.

LJ
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