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How to graph a function with 3 variables
Posted: Wed Sep 29, 2010 4:37 pm
by 13049545
How can you graph a function with 3 variables?
Examle:
thrust = Function(fuelTypeA, fuelTypeB, AirRatio)
I'd like to graph all 3 variables in a 3d chart then have the countour be thrust.
But since you can only use x, y, z values for points I'm not sure if this is possible.
Any ideas or suggestions would be greatly appreciated.
Thanks
ja
Re: How to graph a function with 3 variables
Posted: Thu Sep 30, 2010 10:21 am
by narcis
Hi ja,
I'm not sure about what do you exactly mean here. You could use X, Y and Z values to populate a contour series as described
here. If this doesn't help please give us more detailed information about what you are trying to do.
Thanks in advance.
Re: How to graph a function with 3 variables
Posted: Thu Sep 30, 2010 3:43 pm
by 13049545
So let's say the Z axis is fuel type "A".
And the X axis is fuel type "B"
Which axis would be the "Air Mixture"?
The Y Axis would be thrust.
So even though theirs 3 variables the "Thrust" which is the most important is really the 4th value.
So 3 Variables go into the function to predict thrust and I'd like to graph all 4 numbers if possible.
Thanks,
ja
Re: How to graph a function with 3 variables
Posted: Fri Oct 01, 2010 7:29 am
by narcis
Hi ja,
Do you have an image example of this kind of charts?
Thanks in advance.
Re: How to graph a function with 3 variables
Posted: Fri Oct 01, 2010 2:52 pm
by 13049545
No,
I think due to it's complexity it's always a report.
Probably I should stick to that or lose a variable.
Because I think I'd have to add more axis or another dimension somehow
and just the thought of that hurts my brain.
Thanks,
ja
Re: How to graph a function with 3 variables
Posted: Fri Oct 01, 2010 3:04 pm
by narcis
Hi ja,
Yes, I think that would be a 4 dimension chart. You could make 3 three dimensional charts: one with A, B and T, one with A, C and T and last one with B,C and T. Maybe using this the person who looks at the chart can get an idea of the whole picture. Or maybe a Ternary series could also help here.