Semi Log Scale [Axis Labeling]

[Quant]

Hi,

We have one requirement wherein we need to show the Chart of Semi Log Scale (Logarithmic==True). The required final output should be as shown in following image:

Reuired Semi Log Scale

Actual Semi Log Scale.JPG (33.63 KiB) Viewed 4917 times

TeeChart works fine with Logarithmic Scale, but it does not show axis labels as shown in above image.
Following is the image showing TeeChart with Logarithmic=True:

TeeChart Semi Log Scale

TeeChart Semi Log Scale.JPG (26.61 KiB) Viewed 4914 times

[Christopher]

Hello,

There are several ways to control axis labelling, two of which are shown here:

Code: Select all

    FastLine series1 = new FastLine();
    private void InitializeChart()
    {
      tChart1.Aspect.View3D = false;
      tChart1.Series.Add(series1);
      series1.VertAxis = VerticalAxis.Right;

      Random rnd = new Random();

      for (int i = 0; i < 200; i++)
      {
        series1.Add(i, rnd.Next(10000));
      }

      tChart1.Axes.Right.Increment = 500;
      //tChart1.GetNextAxisLabel += tChart1_GetNextAxisLabel;

      tChart1.Axes.Right.Logarithmic = true;
    }

    void tChart1_GetNextAxisLabel(object sender, GetNextAxisLabelEventArgs e)
    {
      if (((Steema.TeeChart.Axis)sender).Equals(tChart1.Axes.Right))
      {
        e.Stop = false;
        switch (e.LabelIndex)
        {
          case 0:
            e.LabelValue = 50;
            break;
          case 1:
            e.LabelValue = 100;
            break;
          case 2:
            e.LabelValue = 200;
            break;
          case 3:
            e.LabelValue = 500;
            break;
          case 4:
            e.LabelValue = 1000;
            break;
          case 5:
            e.LabelValue = 2000;
            break;
          case 6:
            e.LabelValue = 5000;
            break;
          case 7:
            e.LabelValue = 10000;
            break;
          default:
            e.Stop = true;
            break;
        }
      }
    }

Do either of these strategies help you?